Day 15: Lens Library

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FAQ


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    • @sjmulder
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      21 year ago

      That array initialisation is pure poetry! 😄

      • lwhjp
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        21 year ago

        I’m not fluent in Rust, but is this something like the C++ placement new? Presumably just declaring a table of Vecs won’t automatically call the default constructor? (Sorry for my total ignorance – pointers to appropriate reading material appreciated)

        • @Gobbel2000@feddit.de
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          11 year ago

          You can create an array filled with all the same values in Rust, but only if all values have the same memory representation because they will be copied. That just doesn’t work with Vec’s, because they must all have their own unique pointer. And to have uninitialized values at first (think NULL-pointers for every Vec) while creating each Vec, something like this is apparently needed.

          The appropriate way would certainly have been to store the map as a Vec> instead of an array, but I just wanted to see if could.

          • lwhjp
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            11 year ago

            Ah, I see! Thank you.

  • @sjmulder
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    41 year ago

    C

    Yes, it’s a hash table. Did I pick a language with built in hash tables? Of course I didn’t. Could I have used one of the many libraries implementing one? Sure. But the real question is, can we make do with stuffing things into a few static arrays at nearly zero memory and runtime cost? Yes!

    In the spirit of Fred Brooks, it’ll suffice here to show my data structures:

    struct slot { char label[8]; int lens; };
    struct box { struct slot slots[8]; int nslots; };
    
    static struct box boxes[256];
    

    https://github.com/sjmulder/aoc/blob/master/2023/c/day15.c

  • @cvttsd2si@programming.dev
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    41 year ago

    Scala3

    def hash(s: String): Long = s.foldLeft(0)((h, c) => (h + c)*17 % 256)
    
    extension [A] (a: List[A])
        def mapAtIndex(idx: Long, f: A => A): List[A] =
            a.zipWithIndex.map((e, i) => if i == idx then f(e) else e)
    
    def runProcedure(steps: List[String]): Long =
        @tailrec def go(boxes: List[List[(String, Int)]], steps: List[String]): List[List[(String, Int)]] =
            steps match
                case s"$label-" :: t =>
                    go(boxes.mapAtIndex(hash(label), _.filter(_._1 != label)), t)
                case s"$label=$f" :: t =>
                    go(boxes.mapAtIndex(hash(label), b => 
                        val slot = b.map(_._1).indexOf(label)
                        if slot != -1 then b.mapAtIndex(slot, (l, _) => (l, f.toInt)) else (label, f.toInt) :: b
                    ), t)
                case _ => boxes
        
        go(List.fill(256)(List()), steps).zipWithIndex.map((b, i) =>
            b.zipWithIndex.map((lens, ilens) => (1 + i) * (b.size - ilens) * lens._2).sum
        ).sum
    
    def task1(a: List[String]): Long = a.head.split(",").map(hash).sum
    def task2(a: List[String]): Long = runProcedure(a.head.split(",").toList)
    
  • lwhjp
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    4
    edit-2
    1 year ago

    Haskell

    Took a while to figure out what part 2 was all about. Didn’t have the energy to golf this one further today, so looking forward to seeing the other solutions!

    Solution

    0.3 line-seconds

    import Data.Char
    import Data.List
    import Data.List.Split
    import qualified Data.Vector as V
    
    hash :: String -> Int
    hash = foldl' (\a c -> ((a + ord c) * 17) `rem` 256) 0
    
    hashmap :: [String] -> Int
    hashmap = focus . V.toList . foldl' step (V.replicate 256 [])
      where
        focus = sum . zipWith focusBox [1 ..]
        focusBox i = sum . zipWith (\j (_, z) -> i * j * z) [1 ..] . reverse
        step boxes s =
          let (label, op) = span isLetter s
              i = hash label
           in case op of
                ['-'] -> V.accum (flip filter) boxes [(i, (/= label) . fst)]
                ('=' : z) -> V.accum replace boxes [(i, (label, read z))]
        replace ls (n, z) =
          case findIndex ((== n) . fst) ls of
            Just j ->
              let (a, _ : b) = splitAt j ls
               in a ++ (n, z) : b
            Nothing -> (n, z) : ls
    
    main = do
      input <- splitOn "," . head . lines <$> readFile "input15"
      print $ sum . map hash $ input
      print $ hashmap input
    
  • @hades@lemm.ee
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    3
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    4 months ago

    Python

    0.248 line-seconds (sixth simplest so far after days 6, 2, 1, 4 and 9).

    import collections
    import re
    
    from .solver import Solver
    
    
    def _hash(string: str) -> int:
      result = 0
      for c in string:
        result = (result + ord(c)) * 17 % 256
      return result
    
    def _assert_full_match(pattern: str, string: str):
      m = re.fullmatch(pattern, string)
      if not m:
        raise RuntimeError(f'pattern {pattern} does not match {string}')
      return m
    
    class Day15(Solver):
      input: list[str]
    
      def __init__(self):
        super().__init__(15)
    
      def presolve(self, input: str):
        self.input = input.rstrip().split(',')
    
      def solve_first_star(self) -> int:
        return sum(_hash(string) for string in self.input)
    
      def solve_second_star(self) -> int:
        boxes = [collections.OrderedDict() for _ in range(256)]
        for instruction in self.input:
          label, op, value = _assert_full_match(r'([a-z]+)([=-])(\d*)', instruction).groups()
          box = boxes[_hash(label)]
          match op:
            case '-':
              if label in box:
                del box[label]
            case '=':
              box[label] = value
        return sum((1 + box_idx) * (1 + lens_idx) * int(value)
                    for box_idx, box in enumerate(boxes)
                    for lens_idx, (_, value) in enumerate(box.items()))
    
  • @capitalpb@programming.dev
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    English
    31 year ago

    Had to take a couple days off, but this was a nice one to come back to. Will have to find some time today to go back and do one or two of the 3 that I missed. I don’t have much to say about this one - I had an idea almost immediately and it worked out without much struggle. There’s probably some cleaner ways to write parts of this, but I’m not too disappointed with how it turned out.

    https://github.com/capitalpb/advent_of_code_2023/blob/main/src/solvers/day15.rs

    use crate::Solver;
    use std::collections::HashMap;
    
    #[derive(Debug)]
    struct Lens {
        label: String,
        focal_length: u32,
    }
    
    fn hash_algorithm(input: &amp;str) -> u32 {
        input
            .chars()
            .fold(0, |acc, ch| (acc + ch as u32) * 17 % 256)
    }
    
    pub struct Day15;
    
    impl Solver for Day15 {
        fn star_one(&amp;self, input: &amp;str) -> String {
            input
                .trim_end()
                .split(',')
                .map(hash_algorithm)
                .sum::()
                .to_string()
        }
    
        fn star_two(&amp;self, input: &amp;str) -> String {
            let mut boxes: HashMap> = HashMap::new();
    
            for instruction in input.trim_end().split(',') {
                let (label, focal_length) = instruction
                    .split_once(|ch| char::is_ascii_punctuation(&amp;ch))
                    .unwrap();
    
                let box_number = hash_algorithm(label);
                let lenses = boxes.entry(box_number).or_insert(vec![]);
    
                if focal_length == "" {
                    lenses.retain(|lens| lens.label != label);
                    continue;
                }
    
                let new_lens = Lens {
                    label: label.to_string(),
                    focal_length: focal_length.parse().unwrap(),
                };
    
                if let Some(lens_index) = lenses.iter().position(|lens| lens.label == new_lens.label) {
                    lenses[lens_index].focal_length = new_lens.focal_length;
                } else {
                    lenses.push(new_lens);
                }
            }
    
            boxes
                .iter()
                .map(|(box_number, lenses)| {
                    lenses
                        .iter()
                        .enumerate()
                        .map(|(lens_index, lens)| {
                            (box_number + 1) * (lens_index as u32 + 1) * lens.focal_length
                        })
                        .sum::()
                })
                .sum::()
                .to_string()
        }
    }
    
  • @mykl@lemmy.world
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    3
    edit-2
    1 year ago

    Dart

    Just written as specced. If there’s any underlying trick, I missed it totally.

    9ms * 35 LOC ~= 0.35, so it’ll do.

    int decode(String s) => s.codeUnits.fold(0, (s, t) => ((s + t) * 17) % 256);
    
    part1(List lines) => lines.first.split(',').map(decode).sum;
    
    part2(List lines) {
      var rules = lines.first.split(',').map((e) {
        if (e.contains('-')) return ('-', e.skipLast(1), 0);
        var parts = e.split('=');
        return ('=', parts.first, int.parse(parts.last));
      });
      var boxes = Map.fromEntries(List.generate(256, (ix) => MapEntry(ix, [])));
      for (var r in rules) {
        if (r.$1 == '-') {
          boxes[decode(r.$2)]!.removeWhere((l) => l.$1 == r.$2);
        } else {
          var box = boxes[decode(r.$2)]!;
          var lens = box.indexed().firstWhereOrNull((e) => e.value.$1 == r.$2);
          var newlens = (r.$2, r.$3);
          (lens == null) ? box.add(newlens) : box[lens.index] = newlens;
        }
      }
      return boxes.entries
          .map((b) =>
              (b.key + 1) *
              b.value.indexed().map((e) => (e.index + 1) * e.value.$2).sum)
          .sum;
    }
    
  • @purplemonkeymad@programming.dev
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    3
    edit-2
    1 year ago

    This felt … too simple. I think the hardest part of part two for me was reading comprehension. My errors were typically me not reading exactly was there.

    Python
    import re
    import math
    import argparse
    import itertools
    
    def int_hash(string:str) -> int:
        hash = 0
        for c in [*string]:
            hash += ord(c)
            hash *= 17
            hash = hash % 256
        return hash
    
    class Instruction:
        def __init__(self,string:str) -> None:
            label,action,strength = re.split('([-=])',string)
            self.label = label
            self.action = action
            if not strength:
                strength = 0
            self.strength = int(strength)
        
        def __repr__(self) -> str:
            return f"Instruction(l={self.label}, a={self.action}, s={self.strength})"
        
        def __str__(self) -> str:
            stren = str(self.strength if self.strength > 0 else '')
            return f"{self.label}{self.action}{stren}"
    
    
    class Lens:
        def __init__(self,label:str,focal_length:int) -> None:
            self.label:str = label
            self.focal_length:int = focal_length
    
        def __repr__(self) -> str:
            return f"Lens(label:{self.label},focal_length:{self.focal_length})"
        
        def __str__(self) -> str:
            return f"[{self.label} {self.focal_length}]"
    
    def main(line_list:str,part:int):
        init_sequence = line_list.splitlines(keepends=False)[0].split(',')
        sum = 0
        focal_array = dict[int,list[Lens]]()
        for i in range(0,256):
            focal_array[i] = list[Lens]()
        for s in init_sequence:
            hash_value = int_hash(s)
            sum += hash_value
    
            # part 2 stuff
            action = Instruction(s)
            position = int_hash(action.label)
            current_list = focal_array[position]
            existing_lens = list(filter(lambda x:x.label == action.label,current_list))
            if len(existing_lens) > 1:
                raise Exception("multiple of same lens in box, what do?")
            match action.action:
                case '-':
                    if len(existing_lens) == 1:
                        current_list.remove(existing_lens[0])
                case '=':
                    if len(existing_lens) == 0:
                        current_list.append(Lens(action.label,action.strength))
                    if len(existing_lens) == 1:
                        existing_lens[0].focal_length = action.strength
                case _:
                    raise Exception("unknown action")
    
        print(f"Part1: {sum}")
        #print(focal_array)
    
        sum2 = 0
        for i,focal_box in focal_array.items():
            for l,lens in enumerate(focal_box):
                sum2 += ( (i+1) * (l+1) * lens.focal_length )
    
        print(f"Part2: {sum2}")
    
    
    if __name__ == "__main__":
        parser = argparse.ArgumentParser(description="template for aoc solver")
        parser.add_argument("-input",type=str)
        parser.add_argument("-part",type=int)
        args = parser.parse_args()
        filename = args.input
        if filename == None:
            parser.print_help()
            exit(1)
        part = args.part
        file = open(filename,'r')
        main(file.read(),part)
        file.close()
    
  • janAkali
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    English
    2
    edit-2
    1 year ago

    Nim

    My whole solution can be expressed in just two words: Ordered HashTable

    Total runtime: 0.068 line-seconds (40 LOC * 1.7 ms)
    Puzzle rating: exceptionally confusing description 4/10
    Code: cleaned up solution with types
    Snippet:

    proc getHash(s: string): int =
      for c in s:
        result = ((result + c.ord) * 17) mod 256
    
    proc solve(lines: seq[string]): AOCSolution[int] =
      var boxes: array[256, OrderedTable[string, int]]
      for line in lines:
        block p1:
          result.part1 += line.getHash()
    
        block p2:
          if line.endsWith('-'):
            var name = line.strip(leading=false, chars={'-'})
            boxes[getHash(name)].del(name)
          else:
            let (name, _, value) = line.partition("=")
            boxes[getHash(name)][name] = value[0].ord - '0'.ord
    
      for bi, box in boxes:
        if box.len < 1: continue
        for vi, val in enumerate(box.values):
          result.part2 += (bi+1) * (vi+1) * val
    
  • @LeixB@lemmy.world
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    fedilink
    21 year ago

    Haskell

    import Data.Array
    import qualified Data.ByteString.Char8 as BS
    import Data.Char (isAlpha, isDigit)
    import Relude
    import qualified Relude.Unsafe as Unsafe
    import Text.ParserCombinators.ReadP hiding (get)
    
    hash :: String -> Int
    hash = foldl' (\a x -> (a + x) * 17 `mod` 256) 0 . fmap ord
    
    part1 :: ByteString -> Int
    part1 = sum . fmap (hash . BS.unpack) . BS.split ',' . BS.dropEnd 1
    
    -- Part 2
    
    type Problem = [Operation]
    
    type S = Array Int [(String, Int)]
    
    data Operation = Set String Int | Remove String deriving (Show)
    
    parse :: BS.ByteString -> Maybe Problem
    parse = fmap fst . viaNonEmpty last . readP_to_S parse' . BS.unpack
      where
        parse' = sepBy parseOperation (char ',') &lt;* char '\n' &lt;* eof
        parseOperation =
          munch1 isAlpha
            >>= \label -> (Remove label &lt;$ char '-') +++ (Set label . Unsafe.read &lt;$> (char '=' *> munch1 isDigit))
    
    liftOp :: Operation -> Endo S
    liftOp (Set label v) = Endo $ \s ->
      let (b, a) = second (drop 1) $ span ((/= label) . fst) (s ! hash label)
       in s // [(hash label, b &lt;> [(label, v)] &lt;> a)]
    liftOp (Remove l) = Endo $ \s -> s // [(hash l, filter ((/= l) . fst) (s ! hash l))]
    
    score :: S -> Int
    score m = sum $ join [(* (i + 1)) &lt;$> zipWith (*) [1 ..] (snd &lt;$> (m ! i)) | i &lt;- [0 .. 255]]
    
    part2 :: ByteString -> Maybe Int
    part2 input = do
      ops &lt;- appEndo . foldMap liftOp . reverse &lt;$> parse input
      pure . score . ops . listArray (0, 255) $ repeat []
    
    • lwhjp
      link
      21 year ago

      Nice use of foldMap!