GamerBoy705M to Software Gore@lemmy.worldEnglish • 10 months agoNot good enough for 100%pxscdn.comimagemessage-square29fedilinkarrow-up1540arrow-down16
arrow-up1534arrow-down1imageNot good enough for 100%pxscdn.comGamerBoy705M to Software Gore@lemmy.worldEnglish • 10 months agomessage-square29fedilink
minus-square@halvar@lemm.eelinkfedilink44•edit-210 months agowell 0.9999… is actually 1 because x = 0.9999... 10x = 9.9999... 10x (9.9999...) - x (0.9999...) = 9 9x = 9 x = 1 so 0.9999... is 1
minus-square@RedditWanderer@lemmy.worldlinkfedilink43•10 months agoThis is muuuch better demonstrated by 1/3 = .33… 2/3 = .66… 3/3 = 0.99… “Repeating” matters in approximations
minus-squareexscapelinkfedilink27•10 months agoYes, but 0.99999999999999999999 isn’t 0.999… and therefore not 1, so it’s still wrong.
minus-square@halvar@lemm.eelinkfedilink9•10 months agoThe software is wrong yes. I just had to share this information.
minus-square@halvar@lemm.eelinkfedilink4•10 months agoYou know I didn’t mean it like that, but you are technically right.
minus-square@thedoodlenoodlelink3•10 months agoFirst thing that came to mind was this video by SingingBanana. Great maths channel and he is a frequently on numberphile as well.
well 0.9999… is actually 1 because
x = 0.9999... 10x = 9.9999... 10x (9.9999...) - x (0.9999...) = 9 9x = 9 x = 1 so 0.9999... is 1
This is muuuch better demonstrated by
1/3 = .33… 2/3 = .66… 3/3 = 0.99…
“Repeating” matters in approximations
Yes, but 0.99999999999999999999 isn’t 0.999… and therefore not 1, so it’s still wrong.
The software is wrong yes. I just had to share this information.
your 4th line reads as 10x^2 - x^2 = 9
You know I didn’t mean it like that, but you are technically right.
First thing that came to mind was this video by SingingBanana.
Great maths channel and he is a frequently on numberphile as well.
0.999… is lim(1), not 1.
deleted by creator
What?
1 is a constant so lim(1) = 1